dsaun777
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I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.
The discussion focuses on the spatial gradient of the energy-momentum tensor, specifically the expression ∂βTμυ for β values of 1, 2, and 3 in a 4-D spacetime context. Participants clarify that ∇μTμυ=0 represents conservation, but the specific values of ∂βTμυ depend on the chosen coordinates and the stress-energy tensor. It is established that ∂βTμυ results in a set of 48 numbers, reflecting the complexity of the tensor components. The conversation emphasizes the need for specific conditions to derive meaningful interpretations of the tensor's gradients.
PREREQUISITESPhysicists, mathematicians, and students studying general relativity, particularly those interested in the behavior of energy-momentum tensors and their gradients in theoretical physics.
I hope that you are aware that there is a summation over ##\mu## in the first equation. What do you mean by "what would be..."? It is exactly what you have written, the partial derivative of a function, which is the component of a tensor in some coordinates.dsaun777 said:I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.
I meant what would be the spatial gradient of the energy momentum tensor?martinbn said:I hope that you are aware that there is a summation over ##\mu## in the first equation. What do you mean by "what would be..."? It is exactly what you have written, the partial derivative of a function, which is the component of a tensor in some coordinates.
For some incompressable fluid with density ρ(xμ,t ) at rest what is gradient of the stress energy tensor TαβMatterwave said:There's no general answer to this question...##\partial_\beta T_{\mu\nu}## depends on the stress energy tensor and the coordinates you chose...it's like asking "what's ##d\vec{v}/dt##?" without specifying anything about ##\vec{v}##. It's hard to figure out what you're trying to get at.
At most, I can say, in 4-D spacetime, with the restriction that ##\beta=1,2,3##, then ##\partial_\beta T_{\mu\nu}## is a set of 48 numbers.
T_{\mu\nu:\beta} is covariant component of a three rank tensor allowing $$\beta=0,1,2,3$$ though I do not know if there is a physical meaning on it.dsaun777 said:I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.