dsaun777
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I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.
The discussion revolves around the gradients of the energy-momentum tensor, specifically the expression ∂βTμυ for β values of 1, 2, and 3, without involving time derivatives. Participants explore the implications of the conservation law ∇μTμυ=0 and seek to clarify the meaning and calculation of these gradients in different contexts.
Participants do not reach a consensus on the interpretation and implications of ∂βTμυ, with multiple competing views and uncertainties remaining about its general applicability and physical meaning.
Limitations include the dependence on the specific form of the stress-energy tensor and the coordinate system used, as well as the lack of clarity regarding the physical interpretation of certain tensor components.
I hope that you are aware that there is a summation over ##\mu## in the first equation. What do you mean by "what would be..."? It is exactly what you have written, the partial derivative of a function, which is the component of a tensor in some coordinates.dsaun777 said:I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.
I meant what would be the spatial gradient of the energy momentum tensor?martinbn said:I hope that you are aware that there is a summation over ##\mu## in the first equation. What do you mean by "what would be..."? It is exactly what you have written, the partial derivative of a function, which is the component of a tensor in some coordinates.
For some incompressable fluid with density ρ(xμ,t ) at rest what is gradient of the stress energy tensor TαβMatterwave said:There's no general answer to this question...##\partial_\beta T_{\mu\nu}## depends on the stress energy tensor and the coordinates you chose...it's like asking "what's ##d\vec{v}/dt##?" without specifying anything about ##\vec{v}##. It's hard to figure out what you're trying to get at.
At most, I can say, in 4-D spacetime, with the restriction that ##\beta=1,2,3##, then ##\partial_\beta T_{\mu\nu}## is a set of 48 numbers.
T_{\mu\nu:\beta} is covariant component of a three rank tensor allowing $$\beta=0,1,2,3$$ though I do not know if there is a physical meaning on it.dsaun777 said:I understand, kind of, that ∇μTμυ=0 by conservation or coninuity. What would be ∂βTμυ when β=1,2,3 no time derivative.