Finding the Normal Line for a Curve at a Given Point

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SUMMARY

The discussion focuses on finding the equation of the normal line to the curve defined by the equation y = -3x² at the point (-1, -3). The slope of the tangent line at this point is calculated as 6, leading to the conclusion that the slope of the normal line is -1/6. The final equation of the normal line is determined to be y = -1/6x - 19/6. The relationship between the slopes of perpendicular lines is emphasized as a key concept in deriving the normal line's equation.

PREREQUISITES
  • Understanding of calculus, specifically derivatives
  • Knowledge of the concept of slopes and perpendicular lines
  • Familiarity with quadratic functions
  • Ability to manipulate linear equations
NEXT STEPS
  • Study the process of finding derivatives for various functions
  • Learn about the properties of perpendicular lines in coordinate geometry
  • Explore the concept of normal lines in calculus
  • Practice solving problems involving tangent and normal lines to curves
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in understanding the geometric properties of curves and their tangents and normals.

fatima_a
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find the equation of the normal line to the curve y = -3x^2 at the point (-1,-3).


you have to use derivatives.


i am not asking for the equation of the tangent line i know that is 6x + 3. please show all the steps.

the answer is y = -1/6x - 19/6
 
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Do you know the relationship between the gradient of two perpendicular lines?
 
Another term for gradient in this context is "slope." You can use calculus to find the slope of the tangent line. What is the slope of the line perpendicular to the tangent line? That will be the slope of the line you want. You know a point on this line, so you will have all the information you need to get the equation of this second line.
 
thanks i got it
 

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