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- Thread starter jk22
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- #2

mfb

Mentor

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The force has to be conservative, ##\displaystyle \int_0^\infty \frac{f(\vec e_r)}{r^\alpha} dr## has to be the same for all directions. If you have a weaker gravitational attraction in some direction at some point you need a stronger one in this direction at a different point.

- #3

ohwilleke

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So basically, could the strength of the gravitational pull of an asymmetric galaxy e different in different directions at distances that are near to the galaxy relative to infinity?

If I understand you correctly, yes. It could. But, the formula you use is a point particle formula like the one in your post, and you'd need instead a formula that captures the sum of gravitational pulls from a whole host of different point-like masses. ∑ (f(i)/r

- #4

stefan r

Science Advisor

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If r is measured from the center of the Earth's then gravity does vary. The Moon and Sun cause tides everyday.

Juno's gravity science probe flips your question. It is using differences in gravity to detect the density distribution of mass inside Jupiter.

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