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Equivalent resistors/capacitors etc. tricky problem

  1. Oct 1, 2008 #1
    1. The problem statement, all variables and given/known data
    Find equivalent capacitance between terminals

    2. Relevant equations
    C_eq = C_1 + C_2 for parallel
    C_eq = 1/((1/C_1) + (1/C_2))

    3. The attempt at a solution
    I can't tell what's in parallel and what's in series. That conductor in the center is throwing me off.

    Any help por favor?

    You guys might not be able to see the image because it's pending approval. I uploaded it to imageshack:
    http://img377.imageshack.us/img377/5690/53235366dg9.png [Broken]

    Attached Files:

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    Last edited by a moderator: May 3, 2017
  2. jcsd
  3. Oct 1, 2008 #2


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    Then pluck it out! :mad:

    Hint: Draw it as a figure-of-eight …

    does that have the same potentials? :wink:
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