Estimating Angles of a Box Diagonal

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Homework Statement



Estimate to the nearest degree, the angles that a diagonal of a box with dimensions 10cm x 15cm x 25cm makes with the edges of the box.

Homework Equations



[itex]cos\theta =\frac{u\cdot v}{\left \| u \right \|\left \| v \right \|}[/itex]

The Attempt at a Solution



For the angle between the diagonal vector and the edge with the 10cm side:

[itex]u=(10,0,0)[/itex]
[itex]v=(10,15,25)[/itex]

[itex]cos\theta =\frac{(10,0,0)\cdot (10,15,25)}{\sqrt100\sqrt{100+225+625}}[/itex]
[itex]cos\theta =\frac{100}{10\sqrt{950}}[/itex]

[itex]cos\theta =\frac{10}{\sqrt{950}}[/itex]

Theta = ~71 degrees?

thanks, any help appreciated!
 
Last edited:
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Your denominator should be the product of the lengths of the two vectors. Vector u has length 10, right? Where's that? Vector v has length sqrt(950), why did you edit that to 100sqrt(850)?
 
Vargo said:
Your denominator should be the product of the lengths of the two vectors. Vector u has length 10, right? Where's that? Vector v has length sqrt(950), why did you edit that to 100sqrt(850)?

Oh yeah, I had it right the first time. But if I do that then I can't carry out the next step.. how would you proceed in this question?
 
I edited it now, does it look right?
 
Yeah, that looks right.