- #1

karush

Gold Member

MHB

- 3,269

- 5

to find approximate values of the solution at tt = 0.1, 0.2, 0.3, 0.4, and 0.5.

Compare them to the exact values of the solution at these points.

Given IVP

$$y'+2y=2-{{\bf{e}}^{- 4t}}\quad yt(0)=1$$

ok from a previous post we found that the general solution was

$$y( t ) = 1 + \frac{1}{2}{{\bf{e}}^{ - 4t}} - \frac{1}{2}{{\bf{e}}^{ - 2t}}$$ Steward gives this for Euler's Method so not real sure how to follow this

https://www.physicsforums.com/attachments/8742

Have to go to class, but will back on this when I get back.