Evaluating False Statements on Cyclohexanol's Properties

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SUMMARY

The discussion evaluates the properties of cyclohexanol, specifically its heat of vaporization and entropy values. The heat of vaporization is confirmed as 54 kJ/mol, with absolute entropies for liquid and gas being 200 J/K-mol and 328 J/K-mol, respectively. The false statement identified is that at 80°C, the free energy change for vaporization is negative, which was calculated incorrectly. The correct calculation shows that the free energy change (delta G) at this temperature is +8.797 kJ/mol, confirming statement c as false.

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Homework Statement



Cyclohexanol has a heat of vaporization of 54 kJ/mol and the absolute entropies of the liquid and gas are 200 and 328 J/K-mol, respectively. Which of the following is false?


a. The entropy of vaporization is positive.

b. The heat of formation of liquid cyclohexanol is less than that of the vapour.

c. At 80oC the free energy change for the vaporization is negative.

d. At the boiling point the free energy change for vaporization is zero.

e. At 80oC, cyclohexanol vapour spontaneously condenses into a liquid.


Homework Equations



delta G = delta H - TdeltaS

The Attempt at a Solution



I know statements a, b, and d are true for all substances, so they are not false.

I calculated deltaG at 80degrees and got -45203146 KJ/mol, but that seems a little tp big. I can't figure out where I'm going wrong...

deltaG= 54 Kj/mol - (80 + 273.15 K)(128 J/Kmol)
= 54 KJ/mol- (353.15)(128000KJ/mol)
= -45203146 KJ/mol
 
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Oh, wow... I can't believe I made this mistake... hope it doesn't happen agian; exams are coming up.

I converted to KJ wrong, it should be 128J= 0.128KJ,
and that would make deltaG = + 8.797

So that means that statement c is false. :)
 

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