Evaluating Tanx + Cosx/Sinx = Secx + Cotx

[heelp]

tanx +cosx/sinx = secx + cotx
This is what I have so far

cos^2x sin^2/cos/sin^2x/cos^2x =sinX^2/cosx/sinx^2

Thanks for the help in advance.

 

[matt grime]

You might want to make that more strictly typed.

Not that it really matters, after all, you do know tan is sin/cos, right?

 

[arildno]

Get your parentheses right!
You have the expression:
$$\frac{\tan(x)+\cos(x)}{\sin(x)}$$
To gain your right hand side, just split that fraction into two fractions in the most natural manner.