Expand (x + y/sqrt[n] + z/n)^2

  • Thread starter Algernon81
  • Start date
  • #1
Algernon81
3
0
Hello,

I have come across this part of a question which has puzzled me.

Expand (x + y/sqrt[n] + z/n)^2

I assume it means Taylors, but could someone help me understand this?
 

Answers and Replies

  • #2
Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
12,134
161


Not Taylor's expansion, they just mean to multiply it out:

(x + y/sqrt[n] + z/n) * (x + y/sqrt[n] + z/n) = x2 + . . .​
 
  • #3
Algernon81
3
0


Not Taylor's expansion, they just mean to multiply it out:

(x + y/sqrt[n] + z/n) * (x + y/sqrt[n] + z/n) = ____?​

Ah, typical of me. I always look for the hardest way of doing things.

Thank you!
 
  • #4
statdad
Homework Helper
1,495
36


Not a taylor series - just square the whole thing.

[tex]
\left(x + \frac y {\sqrt n} + \frac z n\right)^2 = \left(x + \frac y {\sqrt n} + \frac z n\right) \cdot \left(x + \frac y {\sqrt n} + \frac z n\right)
[/tex]
 

Suggested for: Expand (x + y/sqrt[n] + z/n)^2

  • Last Post
Replies
5
Views
4K
Replies
3
Views
934
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
14
Views
3K
  • Last Post
Replies
5
Views
10K
Replies
5
Views
2K
  • Last Post
Replies
16
Views
3K
  • Last Post
Replies
5
Views
965
  • Last Post
Replies
2
Views
970
Replies
8
Views
6K
Top