1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Explain how an e.m.f. is induced in the secondary coil

  1. May 27, 2008 #1

    Air

    User Avatar

    1. The problem statement, all variables and given/known data
    The photograph shows a transformer which has been cut in half. The transformer consists of primary and secondary coils wound around the same laminated iron core. The diagram shows a cross-section of the iron core and the two coils. One coil consists of a few turns of thick wire. The other coil has many turns of thinner wire.

    [​IMG]

    a) Explain how an e.m.f. is induced in the secondary coil.

    b) The transformer in the photograph has one coil with 32 turns of thick wire. and the other with 512 turns of thin wire. Either coil can be the primary. with the other being the secondary. Describe the function of the transformer when the 512-turn coil is the primary.

    c) When in use, the 32-turn coil always carries the greater current. Explain why this is so.

    d) Explain why this coil is made with much thicker wire.

    e) Suggest a reason why the core is made of thin laminated sheets of soft iron.


    2. Relevant equations
    None. This is a theory question.


    3. The attempt at a solution
    a) A voltage is provided in the primary coil which produces a current . This changing current causes a magnetic flux in the core. Flux links in the secondary. This changing flux induces a EMF in the secondary coil.

    b) Step down by a factor of 16.

    c) ???

    d) Laminated reduces eddy current. Thin hence reduces it further. Soft iron strengthen the flux.


    4. The problem with this question
    I don't understand what question (c) is asking for? Can I be guided in the right direction. Thanks in advance.
     
    Last edited: May 27, 2008
  2. jcsd
  3. May 27, 2008 #2
    The power is the same for both primary and secondary coils. You know the transformer winding ratio, right?

    Vs/Vp=Ns/Np

    From this you can tell that fewer turns will have a lower voltage. To keep the same power the current has to increase.

    P=IE

    More current means bigger wire.
     
  4. May 27, 2008 #3

    Air

    User Avatar

    So, thicker wire provides greater power as the current is large within it?
     
  5. May 27, 2008 #4
    No the power will be the same on both sides of the transformer (ignoring losses). The thicker wire is needed to carry the larger current without overheating. P=IE or P=IV
     
  6. May 27, 2008 #5

    Air

    User Avatar

    Oh, I see. So, a thicker wire is needed so that the same power can be obtained as the thin wire transformer (which has larger turns). The thicker wire are sort of substitution for less turns. Is that correct?
     
  7. May 27, 2008 #6
    Not really. The thin and thick wire are in the same transformer. The winding of the transformer with the most turns will be at a higher voltage with a lower current. And the winding with the fewest turns will be at a lower voltage with more current.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Explain how an e.m.f. is induced in the secondary coil
  1. Induced E.M.F. (Replies: 14)

Loading...