Explain Why (7÷4)÷(1÷2)=7÷4÷1×2 | Fractions

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In summary: Okay, in summary, when dividing by a fraction, we can rewrite it as multiplying by the reciprocal of that fraction. Therefore, (7/4)/(1/2) = (7/4) * (2/1) = (7/2).
  • #1
eddie159
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Can someone please explain why the following equation is true:

[itex] (7 \div 4) \div (1 \div 2) = 7 \div 4 \div 1 \times 2 [/itex]

As in, why does the division become multiplication when the parentheses are removed?Thanks
 
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  • #2
Dividing by something is the same as multiplying by the inverse (by definition), and the inverse of 1/2 is 2/1. Therefore, (7/4)/(1/2) = (7/4) * (2/1) = (7/4)*2/1 = ((7/4)/1)*2.
 
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  • #3
Thanks!

mfb said:
Dividing by something is the same as multiplying by the inverse (by definition), and the inverse of 1/2 is 2/1. Therefore, (7/4)/(1/2) = (7/4) * (2/1) = (7/4)*2/1 = ((7/4)/1)*2.
 
  • #4
eddie159 said:
Thanks!

I can't resist to say that ##a \div b## is an ugly and often confusing notation. Rather, we use ##\frac{a}{b}##
 
  • #5
When we divide a fraction by another fraction, we have to multiply first fraction by the reciprocal of second fraction.
i.e. $$\dfrac{a}{b}\div \dfrac{m}{n}=\dfrac{a}{b}\times \dfrac{n}{m}$$
so $$(7\div 4)\div (1\div 2)=\dfrac{7}{4}\div \dfrac{1}{2}=\dfrac{7}{4}\times \dfrac{2}{1}$$
 
  • #6
Math_QED said:
I can't resist to say that ##a \div b## is an ugly and often confusing notation. Rather, we use ##\frac{a}{b}##
I totally agree.
 
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  • #7
Dividing a fraction by another fraction is same as multiplying reciprocal of another fraction. So,

##\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{\dfrac{7}{4}}{1}\times2##

##\implies\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{14}{4}##

##\implies\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{14}{4}##

##\implies\dfrac{\dfrac{7}{4}}{1}\times2=\dfrac{14}{4}##
 
  • #8
You have a lot of extra work here that isn't needed.
Deepak suwalka said:
Dividing a fraction by another fraction is same as multiplying reciprocal of another fraction. So,

##\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{7}{4}\times\dfrac{2}{1}##
##=\frac 7 2##
Done...
Deepak suwalka said:
##=\dfrac{\dfrac{7}{4}}{1}\times2##

##\implies\dfrac{7}{4}\div\dfrac{1}{2}=\dfrac{14}{4}##

##\implies\dfrac{7}{4}\times\dfrac{2}{1}=\dfrac{14}{4}##

##\implies\dfrac{\dfrac{7}{4}}{1}\times2=\dfrac{14}{4}##
With all of this extra, unnecessary work, you at least could have simplfied your final result.
 

Question 1: What is the order of operations when solving this fraction equation?

In this equation, the order of operations is parentheses, exponents, multiplication and division (from left to right), and then addition and subtraction (from left to right). This means that the nested fraction within the parentheses should be solved first, followed by the division and multiplication on the outside.

Question 2: Why does the order of operations matter in this equation?

The order of operations is important because it determines the correct sequence in which the operations should be performed. If the operations are not performed in the correct order, it can result in an incorrect answer.

Question 3: How do you solve the nested fraction within the parentheses?

To solve the nested fraction, you must first invert the fraction and multiply it by the fraction outside of the parentheses. This means that (1/2) becomes (2/1) and then you multiply it by (7/4), resulting in (7/2). This then simplifies the equation to (7/2) ÷ (1/2).

Question 4: How do you simplify (7/2) ÷ (1/2)?

To simplify this expression, you must multiply the first fraction by the reciprocal of the second fraction. This results in (7/2) x (2/1) which simplifies to 7/1 or simply 7.

Question 5: Can this equation be written in a different way?

Yes, this equation can also be rewritten as (7/4) ÷ (1/2) = (7/4) x (2/1) which follows the same steps as described above and also results in the answer of 7. This shows that the order of operations can be rearranged as long as the operations are performed in the correct sequence.

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