A Extra terms in the Action in Zee chapter 1.3?

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The tau and sigma terms in the expression are arbitrary coupling constants that originate from the self-interaction energy V of the field φ, as expressed in equation (2). They represent the self-interaction part of the arbitrary function V in a series of φ. Additionally, there is confusion regarding the transition from 3-momentum to 4-momentum in the Sidney Coleman lectures, specifically why the operator on the right side is dropped. This transition typically involves simplifying the expression under certain assumptions about the momentum operators. Understanding these concepts is crucial for grasping the underlying physics in the context of quantum field theory.
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Hi, could someone please explain where the tau and sigma terms come from in this expression:

Screen Shot 2019-09-20 at 10.47.53 PM.png

I see the kinetic energy and quadratic "mattress" potential terms, but the tau and sigma kinda come out of nowhere. Where are they from?
 
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These are just arbitrary coupling constants. They originate from the self interaction energy V of the field ##\varphi## with itself in equation (2). It is a way of expressing the self interaction part of the arbitrary function V in a series of ##\varphi##.
 
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Hans de Vries said:
These are just arbitrary coupling constants. They originate from the self interaction energy V of the field ##\varphi## with itself in equation (2). It is a way of expressing the self interaction part of the arbitrary function V in a series of ##\varphi##.

Thanks that makes sense.

I was wondering if anyone could address another question I had?
This one is from the Sidney Coleman lectures (2.72)

##e^{i P . x}\alpha(p)e^{-i P . x} = e^{-i p . x}\alpha(p)##

i'm confused why we drop the operator on the right side when we go from 3-momentum to 4-momentum?
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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