Solving for Time in Scalar Product Equation

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SUMMARY

The discussion centers on solving for time (t) in the scalar product equation d = !(v + 0)t, where d = 0.984 and v = 1.9. The participant initially misinterprets the "!" symbol, leading to confusion in their calculations. A suggestion is made to consider the equation as d = |(v + 0)t|, which clarifies that d represents the scalar product of velocity and time. This adjustment is crucial for correctly solving for t.

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Homework Statement


I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"



Homework Equations


d = !(v + 0)t;



The Attempt at a Solution


In a problem with different numbers I was able to solve for t by dividing and ignoring the "!", then multiply by 2 for the answer.
.984/1.9= .518
.518 * 2 = 1.036 but this does not work.
 
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hi kkershaw

not too sure what you're trying to do - can you explain the whole problem...?
 
kkershaw said:

Homework Statement


I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"

Are you sure it's not

d = |(v + 0)t| ?

expressing d as a scalar product of velocity (speed) and time?
 

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