- #36
garrett
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A "deformation" of a Lie group is meant in the same way that our lumpy spacetime is a deformation of de Sitter spacetime.
garrett said:A "deformation" of a Lie group is meant in the same way that our lumpy spacetime is a deformation of de Sitter spacetime.
Hello Jimster41,Jimster41 said:I'm just a layperson trying to get a sense of what what the view is here. Your paper has sent me into a fugue of wikipedioia.
is there any intuitive way to understand (enough to appreciate the view) the difference between the number of dimensions and the number of roots, of an algebraic structure like the e8?
Yes, in physics, the roots, and specifically the eigenvalues with respect to the mutually commuting generators, correspond to elementary particle charges.Your statement above seems relevant to my confusion here, I have been trying to tie the E8 and representation theory to the experience of looking at objects in the world. I get the idea that the algebra describes the constrained behavior of a set of objects - potentially those objects are the basis of the SM, the fundamental structures of matter in space time.
This is a harder question. The best answer I know of comes from quantum mechanics, which basically says nature tries everything.If that is in some sense getting the meaning of it, Do you have any thoughts on what process is causing deformation? What is causing the evolution of species, as it were, such that we don't just have the raw basis, but instead... The world with all its richness, in time. Is there a sense in which the algebra must be "run"?
E8(8) said:Can you give a a precise definition of what you mean by "deformation of E_8"? What you just said does not seem to have any sense. Can you at least point out to a mathematical reference where such concept is defined and explored?
E8(8) said:My objection is not vague. What do you mean by "variations of the Maurer-Cartan form"? How is that related to deforming the underlying Lie group? Can you give a mathematical reference were such concept is defined and explored?
Jimster41 said:Sorry if I this covered in the paper, does the deforming Spin(1,4) Lie group containing the rigid Spin(1,3) sub algebra have to be DeSitter to work, to allow GR to be represented as the Cartan Connection between them (I hope that's not butchering it too much), or can it also/instead be AdS?
garrett said:Yes, the main idea and mathematical formulation of Cartan geometry has been explored in many previous works, perhaps most extensively in Sharpe's book on the subject. What is provided in LGC is a generalization and application to physics.
I prefer the descriptive "deforming" to "lumpy," but the concept is the same. Perhaps you should compose a note to Sharpe to inform him that his work is nonsense.A Cartan geometry on [itex]M[/itex] consists of a pair [itex](P, \omega)[/itex], where [itex]P[/itex] is a principal bundle [itex]H \to P \to M[/itex] and [itex]\omega[/itex], the Cartan connection, is a differential form on [itex]P[/itex]. The bundle generalizes the bundle [itex]H \to G \to G/H[/itex] associated to the Klein setting, and the form [itex]\omega[/itex] generalizes the Maurer-Cartan form [itex]\omega_G[/itex] on the Lie group [itex]G[/itex]. In fact, the curvature of the Cartan geometry, defined as [itex]\Omega = d \omega + \frac{1}{2} [\omega, \omega][/itex], is the complete local obstruction to [itex]P[/itex] being a Lie group.
The manifold [itex]P[/itex] may be regarded as some sort of “lumpy Lie group” that is homogeneous in the [itex]H[/itex] direction. Moreover, [itex]\omega[/itex] may be regarded as a “lumpy” version of the Maurer-Cartan form. The Cartan connection, [itex]\omega[/itex], restricts to the Maurer-Cartan form on the fibers and hence satisfies the structural equation in the fiber directions; but when [itex]Ω \ne 0[/itex] we lose the “rigidity” that would otherwise have been provided by the structural equation in the base directions and that would have as a consequence that, locally, [itex]P[/itex] would be a Lie group with [itex]\omega[/itex] its Maurer-Cartan form. Thus, the curvature measures this loss of rigidity.
garrett said:The LGC idea begins with Cartan geometry, as a deformation (or excitation) of a Lie group [itex]G'[/itex], and then generalizes to what can happen when [itex]G'[/itex] is a subgroup of a larger group, [itex]G[/itex]. And, yes, it's simple, and, yes, that's all one needs to build a ToE.
This is an oversimplified criticism, hence unhelpful. Of course a Cartan geometry has an underlying manifold, but it has more structure. One equips the tangent bundle with an (abstract) Ehresmann connection to distinguish horizontal/vertical directions in a coordinate-independent way. Then one specializes the Ehresmann connection to be a Cartan connection with extra, more concrete, properties) to bring the framework closer to physics. The fact that a Cartan connection can be regarded in terms of Lie group deformation theory is not "absurd". (Whether this point of view is in fact useful for real world physics remains to be seen, but let us keep the criticisms on an informed and constructive level.)E8(8) said:The abstract of [Garrett's] paper: "Our universe is a deforming Lie group.", can be thus rewritten as:
"Our universe is a manifold."
Because a Cartan geometry has as underlying space a manifold.
strangerep said:This is an oversimplified criticism, hence unhelpful. Of course a Cartan geometry has an underlying manifold, but it has more structure. One equips the tangent bundle with an (abstract) Ehresmann connection to distinguish horizontal/vertical directions in a coordinate-independent way. Then one specializes the Ehresmann connection to be a Cartan connection with extra, more concrete, properties) to bring the framework closer to physics. The fact that a Cartan connection can be regarded in terms of Lie group deformation theory is not "absurd". (Whether this point of view is in fact useful for real world physics remains to be seen, but let us keep the criticisms on an informed and constructive level.)
I've now finished a first pass through the paper. I agree that the above is "what he is really doing". Although there are some vague allusions to something beyond that, they are embryonic at best and therefore strike me as far too speculative.E8(8) said:[Garrett] should have written an abstract saying something like:
"We consider a classical cosmological model based on a Cartan geometry with group..."
which is what he is really doing
Please give some specific references in his paper where he makes mathematical mistakes.(although he is not doing it right because he does not know the mathematics involved).
Yes. Although he mentions "superposition" of 3 "spacetime-like" regions inside the large group, I did not see a proper development of that idea, certainly no unitary rep structures, or whatever.I know that a Cartan geometry has more structure than a manifold, in particular it is a fiber bundle, but that does not change the fat that the underlying space is a manifold and that the structure is completely classical.
I agree that it is not a TOE, but perhaps my sense of humor is not as harsh as yours.Saying that he has obtained "TOE" just because he is considering a model which is fiber bundle with a connection is again, a hilarious joke.
Well, I do not consider it a waste of my time -- it forced me to clarify some aspects of my own understanding of Cartan geometry.You are wasting your time reading that paper;
I did indeed perceive that (especially) the later sections where he describes his theory (after the general framework) were rather rambling. OTOH, I have read other poorly written papers that nevertheless contained a seed of an idea, or a different angle on an old idea, that stimulated my own thoughts. So, again, I don't consider reading Garrett's paper to have been a waste of my time. Nevertheless, YMMV.it is very poorly written,
Again, please give some specific references in his paper where he commits mathematical inconsistencies.it is inconsistent
I agree that in its present classical form, it is not a TOE.and for sure, it is not a TOE.
I was referring to the success of the Spin(10) GUT in several different aspects; specifically, in the appearance of correct Standard Model hypercharges when fermions are assigned to the 16 rep space, the roughly correct weak mixing angle, and in roughly convergent coupling constant strengths. Of course, there are deficiencies, such as the non-observance of proton decay, so the degree to which the Spin(10) GUT can be considered a success is certainly a matter of opinion.strangerep said:I was also a bit disturbed early in the paper by how Garrett describes SU(10) GUT as a "success". I would have thought the opposite was true.
In general, I think a Lie group deformation can be thought of as, essentially, a modification of a Lie group's Maurer-Cartan form. This is different than a modification of the structure constants.strangerep said:For other readers who were wondering what "Lie Group deformation" means, it's essentially a procedure of (continuously) modifying the structure constants of the Lie algebra.
I mean rigid in the same sense as Sharpe, in that the relevant curvature of the connection vanishes, and the geometric structure of the corresponding subgroup or subspace is preserved.I've also seen (elsewhere) the term "rigid" used to mean "Lie-stable" in the above sense. I notice you use the term "rigid" for subgroups. Do you mean "rigid" in the above sense, or with some other meaning?
There are a few twists here. First, when thinking about the Ehresmann-Cartan connection, the relevant "base manifold," over which it is described, is the deforming Lie group Manifold. What has happened is that the Maurer-Cartan form over the Lie group manifold, valued in the Lie algebra, has varied in a nontrivial way to become the Ehresmann-Cartan connection, which is still valued in the same Lie algebra but now describes the geometry of a deforming Lie group manifold and not the Lie group manifold. As a map, the Ehresmann-Cartan connection maps vectors on the deforming Lie group manifold to Lie algebra elements.Question: since the maximal subgroup ##H## on a fibre is the same for all points of the base manifold, is the Ehresmann--Cartan connection therefore essentially equivalent to the "linear mapping of generators among themselves" that I mentioned above?
Apologies. I'm in the bad habit of only numbering equations I refer to later, which makes it harder for others to refer to the unnumbered equations.Would you please number ALL of your equations? Incomplete equation numbering makes it annoyingly cumbersome to discuss details...
Best way to keep track of them is to think of them with respect to their corresponding connection. (Of which there are many.)strangerep said:@garrett: OK, another question: I'm up to p20 and getting a bit confused by the various "curvatures".
Yes, the curvature of the de Sitter connection includes the torsion, and the Riemann curvature, AND minus the frame squared. Because the torsion vanishes and the Riemann curvature equals the frame squared for de Sitter spacetime, the curvature of the de Sitter connection vanishes while the Riemann curvature does not.You say (top of p20) that "the curvature of the de Sitter connection vanishes", which superficially contradicts the fact that curvature of ordinary de Sitter spacetime does not vanish. I'm guessing this is because there's more than one "curvature" involved here? I.e., the curvature ##F(x)## of the Cartan connection over ##M## given by your eq(8.7) which involves both the Riemann curvature ##R## and the torsion ##T##?
Correct.Edit: next question: on p24 you use the adjective "wavy" to describe ##G'/H##. This term is not defined, afaict. I'm guessing you mean that deformations are applied to ##G'/H##, but not to ##H## nor to ##G/G'## ?