Find and P ((1-sqrt3 i)1-i) in Complex Analysis homework

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SUMMARY

The discussion centers on the evaluation of the expression P((1 − √3 i)^(1−i)) in complex analysis. Participants express uncertainty regarding the meaning of the operator P, concluding it is not a standard mathematical function. The evaluation provided simplifies to e^(1−i)(ln 2 − π/3 i), demonstrating that the expression can be computed without the P operator. The conversation highlights the importance of understanding notation in complex analysis.

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nickolas2730
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I have a homework question:
Find (1 − \sqrt{3} i)1−i and P((1 − \sqrt{3} i)1−i).

I don't know what does the P stand for, And i can't find it in the textbook either.

Thanks
 
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Welcome to PF, nickolas2730! :smile:

I have no clue what P stands for either.
I dare to say it is not a standard mathematical operator or function.
So you'll have to find it in your notes or else.
 
I like Serena said:
Welcome to PF, nickolas2730! :smile:

I have no clue what P stands for either.
I dare to say it is not a standard mathematical operator or function.
So you'll have to find it in your notes or else.

Thank you so much, i have handed it in already lol
and waiting for answer and see what on Earth does that P stand for
 
Let me know if you find out, will you? :wink:
 
sure!
btw, thanks for helping me for the homework question b4
 
P ((1 −√3i)1−i) = e(1−i)Log(1−√3i)
= e(1−i)(ln 2− ∏/3 i)
= eln 2−∏/3 e−(ln 2+∏/3)i
 
Funny.
This is just the evaluation of the expression.
Without P() it would say exactly the same.
 

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