Find Balloon Height: Darshan Amin's Question on Yahoo Answers

  • Context: MHB 
  • Thread starter Thread starter MarkFL
  • Start date Start date
  • Tags Tags
    Balloon Height
Click For Summary
SUMMARY

The discussion addresses the mathematical proof for calculating the height of the center of a round balloon based on its radius and angles subtended by an observer. The formula derived is h = r * sin(β) * cosec(α/2), where r is the radius, β is the angle of elevation, and α is the angle subtended at the observer's eye. Key steps include using the sine function to relate height and distance, ultimately leading to the desired height equation. The proof is validated through substitution and trigonometric identities.

PREREQUISITES
  • Understanding of basic trigonometry, including sine and cosecant functions.
  • Familiarity with geometric concepts related to angles and circles.
  • Ability to manipulate algebraic expressions and perform substitutions.
  • Knowledge of how to interpret and construct geometric diagrams.
NEXT STEPS
  • Study advanced trigonometric identities and their applications in geometry.
  • Explore the properties of circles and angles in relation to observers.
  • Learn about the derivation of formulas in spherical geometry.
  • Investigate practical applications of trigonometry in real-world scenarios, such as balloon physics.
USEFUL FOR

Students of mathematics, educators teaching geometry and trigonometry, and anyone interested in applying mathematical proofs to real-world problems involving angles and heights.

MarkFL
Gold Member
MHB
Messages
13,284
Reaction score
12
Here is the question:

A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its?


A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its centre is β.prove that the height of the centre of the balloon is r*sinβ*cosecα*1/2

I have posted a link there to this thread so the OP can view my work.
 
Mathematics news on Phys.org
Hello Darshan Amin,

Please consider the following diagram:

View attachment 1804

From this we see:

(1) $$\sin(\beta)=\frac{h}{d}\implies h=d\sin(\beta)$$

(2) $$\sin\left(\frac{\alpha}{2} \right)=\frac{r}{d}\implies d=r\csc\left(\frac{\alpha}{2} \right)$$

Substituting for $d$ from (2) into (1) we obtain:

$$h=r\csc\left(\frac{\alpha}{2} \right)\sin(\beta)=r\sin(\beta) \csc\left(\frac{\alpha}{2} \right)$$

Shown as desired.
 

Attachments

  • darshan.jpg
    darshan.jpg
    6 KB · Views: 96

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
1
Views
10K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
1
Views
6K
Replies
2
Views
2K
Replies
3
Views
5K