MHB Find Balloon Height: Darshan Amin's Question on Yahoo Answers

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The discussion centers on a mathematical problem involving the height of a balloon's center based on its radius and angles subtended at the observer's eye. The solution involves deriving the height using trigonometric relationships, specifically the sine function for angles β and α. The key equations show that the height (h) can be expressed as h = r*sin(β)*cosec(α/2). A diagram is referenced to aid understanding of the relationships between the variables. The thread provides a clear proof of the height formula, confirming its accuracy.
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Here is the question:

A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its?


A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its centre is β.prove that the height of the centre of the balloon is r*sinβ*cosecα*1/2

I have posted a link there to this thread so the OP can view my work.
 
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Hello Darshan Amin,

Please consider the following diagram:

View attachment 1804

From this we see:

(1) $$\sin(\beta)=\frac{h}{d}\implies h=d\sin(\beta)$$

(2) $$\sin\left(\frac{\alpha}{2} \right)=\frac{r}{d}\implies d=r\csc\left(\frac{\alpha}{2} \right)$$

Substituting for $d$ from (2) into (1) we obtain:

$$h=r\csc\left(\frac{\alpha}{2} \right)\sin(\beta)=r\sin(\beta) \csc\left(\frac{\alpha}{2} \right)$$

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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