MHB Find Balloon Height: Darshan Amin's Question on Yahoo Answers

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The discussion centers on a mathematical problem involving the height of a balloon's center based on its radius and angles subtended at the observer's eye. The solution involves deriving the height using trigonometric relationships, specifically the sine function for angles β and α. The key equations show that the height (h) can be expressed as h = r*sin(β)*cosec(α/2). A diagram is referenced to aid understanding of the relationships between the variables. The thread provides a clear proof of the height formula, confirming its accuracy.
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Here is the question:

A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its?


A round balloon of radius r subtends an angle α at the eye of observer while the angle of elevation of its centre is β.prove that the height of the centre of the balloon is r*sinβ*cosecα*1/2

I have posted a link there to this thread so the OP can view my work.
 
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Hello Darshan Amin,

Please consider the following diagram:

View attachment 1804

From this we see:

(1) $$\sin(\beta)=\frac{h}{d}\implies h=d\sin(\beta)$$

(2) $$\sin\left(\frac{\alpha}{2} \right)=\frac{r}{d}\implies d=r\csc\left(\frac{\alpha}{2} \right)$$

Substituting for $d$ from (2) into (1) we obtain:

$$h=r\csc\left(\frac{\alpha}{2} \right)\sin(\beta)=r\sin(\beta) \csc\left(\frac{\alpha}{2} \right)$$

Shown as desired.
 

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