Find moment of Inertia from Force, radius and acceleration

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iva
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Homework Statement




A disc shaped object is made of a non-uniform material. Its radius is r and it is fre to rotate about an axis through its centre. If a force F applied tangentially at the edge of the object produces the angular acceleration a, what is its moment of inertia for rotation about the axis?


Homework Equations



I=mr2
F=ma

The Attempt at a Solution



If F=ma then m=F/a

so that i=mr2 becomes I=Fr2/a

The answer in the book is I=Fr/a

Where did i go wrong? is it something to do with the force being tangent to the disc that i didn't do something?

Thanks!
 
on Phys.org
iva said:
If F=ma then m=F/a
Careful. "a" is the angular acceleration, not the linear acceleration. (It's better to use alpha for angular acceleration.) What's Newton's law for rotation?

so that i=mr2 becomes I=Fr2/a
That formula for moment of inertia does not apply here.

All you need is Newton's 2nd law for rotation.
 
Thanks i get it now,

So all i really needed was 1 equation:

rotational force equation: r* F=I * alpha so I=rF/alpha right?