Find Probability of Item Weight in Normal Distribution | Statistics Help

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The discussion focuses on calculating the probability of item weights within a normal distribution defined by a mean (μ) of 12 ounces and a standard deviation (σ) of 2 ounces. The user aims to determine the probability that 3 out of 7 independent items fall within the weight range of 8 to 16 ounces. The calculations provided utilize the Z-transformation formula Z=(X-μ)/σ, resulting in a probability of approximately 0.9544 for the specified range.

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need help with this problem
x~normal(mean= 12, stdev=2)
item weight from 8 to 16 ounces
i have a random sample of 7 items and need to find the probability that 3 of those items fulfill the weight
each item is independent

this is what i got at the moment
z=(16-12)/(2) = 2
p(z<2)-p(z<-2)
=.9772-.0228
=.9544
 
Last edited:
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You need to use the transformation Z=(X-μ)/σ, and then read the range off of your table.

(σ = std.dev, and μ=mean)
 

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