MHB Find the 79th term in the sequence

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The discussion focuses on finding the 79th term in the arithmetic sequence 7, -4, -1. The formula used is a_n = a_1 + (n-1)d, with a_1 set to -7 and d as -3. The calculation shows that a_{79} equals 227. A participant points out a typo in the formula, clarifying it should be a_n = a_1 + (n-1)d. The thread concludes with the corrected formula being acknowledged.
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Find the 79th term in the sequence - 7, - 4, - 1
$$a_n=a_1+\left(a_n-1 \right)d$$
$$n=79,\ \ a_1=-7, \ \ d=-3$$
$$a_{79}=-7+\left(79-1\right)\left(3\right)=227$$

I just followed an example?
 
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karush said:
Find the 79th term in the sequence - 7, - 4, - 1
$$a_n=a_1+\left(a_n-1 \right)d$$
$$n=79,\ \ a_1=-7, \ \ d=-3$$
$$a_{79}=-7+\left(79-1\right)\left(3\right)=227$$

I just followed an example?

There is a typo
$a_n=a_1+\left(n-1 \right)d$

rest is OK
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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