Find the 79th term in the sequence

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SUMMARY

The 79th term in the arithmetic sequence defined by the first term \(a_1 = -7\) and a common difference \(d = -3\) is calculated using the formula \(a_n = a_1 + (n-1)d\). Substituting \(n = 79\) yields \(a_{79} = -7 + (79-1)(-3) = 227\). A correction was noted regarding the formula, which should be \(a_n = a_1 + (n-1)d\) instead of \(a_n = a_1 + (a_n-1)d\). The calculation confirms the accuracy of the result.

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karush
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Find the 79th term in the sequence - 7, - 4, - 1
$$a_n=a_1+\left(a_n-1 \right)d$$
$$n=79,\ \ a_1=-7, \ \ d=-3$$
$$a_{79}=-7+\left(79-1\right)\left(3\right)=227$$

I just followed an example?
 
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karush said:
Find the 79th term in the sequence - 7, - 4, - 1
$$a_n=a_1+\left(a_n-1 \right)d$$
$$n=79,\ \ a_1=-7, \ \ d=-3$$
$$a_{79}=-7+\left(79-1\right)\left(3\right)=227$$

I just followed an example?

There is a typo
$a_n=a_1+\left(n-1 \right)d$

rest is OK
 
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