Find the acceptable concentration of CO

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SUMMARY

The acceptable hourly average concentration of carbon monoxide (CO) is established at 35 mg/m³ according to the National Ambient Air Quality Objectives. To convert this concentration to parts per million (ppm) at -30 °C and 0.92 atm, one must first calculate the concentration in mg/m³ under these conditions. The relevant equation involves the ideal gas law, PV = nRT, and requires adjustments for temperature and pressure to derive the ppm value. The ambiguity in the question regarding whether the concentration is expressed in volume/volume (v/v) or weight/volume (w/v) complicates the calculation.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of concentration units (mg/m³, ppm)
  • Familiarity with temperature and pressure conversions
  • Basic arithmetic and algebra skills for unit conversions
NEXT STEPS
  • Learn to apply the ideal gas law for concentration conversions.
  • Study the relationship between temperature, pressure, and gas volume.
  • Research the definitions and calculations of ppm in different contexts.
  • Explore resources on air quality standards and their implications for environmental science.
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Environmental scientists, chemistry students, and professionals involved in air quality management will benefit from this discussion, particularly those focused on understanding gas concentrations and regulatory standards.

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Homework Statement


Based on the “National Ambient Air Quality Objectives”, the acceptable hourly average concentration of carbon monoxide (CO) is 35 mg/m^3.

Find the acceptable concentration of CO in ppm if the temperature is -30 °C and pressure is 0.92 atm.

Express the concentration as a percent by volume.

Homework Equations


PV = nRT (maybe)

The Attempt at a Solution


Hello, everyone!

Could someone please help me understand how to do the problem above?

So far, I get the following.:
101.325 kPa * V = (35E-3 g / 28.01 g) mol * 8.31 kPa L / (mol K) * (-30 + 273.15) K

V = 0.0249180252056537913 L

Am I on the right track? If so, what do I do next? If not, then what must I do?

Any input would be greatly appreciated!
 
Last edited:
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Write the ppm definition.
 
Right equation, otherwise not really. We often get questions supposedly of chemistry here which are really problems of arithmetic that students learned years before starting chemistry.

You are given a concentration in mg/m-3 at one T and P. You want to know in the first place the mg /m-3 at another T, P. That is per unit volume - the volume in question, that is the m3 doesn't change. From your equation in 2 what remains the same between the two situations is P/R, can you see? That is the main bit of non-arithmetical knowledge. The other is knowing what is really meant by T in this context. :oldwink:

Work out the new mg/m-3 then what that is in ppm.
 
Last edited:
epenguin said:
You are given a concentration in mg/m-3 at one T and P.

Not exactly, original T and P are not given.

epenguin said:
Work out the new mg/m-3 then what that is in ppm.

As original statement doesn't contain any additional information, I am ready to assume it is to be understood as "35 mg/m3 at any conditions".

It doesn't say anything about whether is it ppm v/v or w/w, which makes it ambiguous and impossible to answer.
 
The way I read the question is 35 mg / m^3 at standard conditions is the legislative rule, and that what is sought is the adaption of the legislative rule to the new conditions ( -30 °C and 0.92 atm pressure).

Edit:
As for the ppm formula that you're asking for, according to this link ( https://sciencing.com/calculate-ppm-5194302.html ), it's weight / volume * 10^6.
 
s3a said:
The way I read the question is 35 mg / m^3 at standard conditions is the legislative rule, and that what is sought is the adaption of the legislative rule to the new conditions ( -30 °C and 0.92 atm pressure).

I am not convinced about the STP part, but you can definitely try this way. Note, that 35 mg of CO at STP means some easy to calculate volume in a well defined volume of air (1 m3). If you change T, P you change it for both gases. Will the ratio of volumes CO/air change? Will the molar ratio of CO/air change? Will the mass ratio of CO/air change? Does it make any sense to make these calculations?

As for the ppm formula that you're asking for, according to this link (...), it's weight / volume * 10^6.

Weight over volume - what units for weight, what units for volume? As long as they are not well defined there is no way to have an unambiguous result.

Compare http://www.chembuddy.com/?left=concentration&right=ppm-ppb-ppt

I still think assuming it is 35 mg per cubic meter of air regardless of T, P is the only way to add sense to the question.
 

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