Find the derivative of V = ay/(b² + y²)

[Kali8972]

Partial integral?

Can someone help me figure out what this means? It's been forever since I've had any math classes.

V= ay/(b2 + y2)

Find the derivative in terms of a,b, and y

Thanks so much!

 

[amcavoy]

Can someone help me figure out what this means? It's been forever since I've had any math classes.
V= ay/(b2 + y2)
Find the derivative in terms of a,b, and y
Thanks so much!

Do you know what a derivative is? Nobody here is going to just do the problem for you, but if you show what you're having trouble with we'll try to help

 

[Kali8972]

yes... For example if you had 2x^3 the derivative would be 6x^2... When i do the derivative for the above equation I get:
a(b^2-y^2)/(b^2+y^2)^2

 

[HallsofIvy]

Use the "quotient rule": the derivative of $\frac{f(y)}{g(y)}$ is
$$\frac{\frac{df}{dy}g(y)- f(y)\frac{dg}{dy}}{g^2}$$