Find the Detect Fake Coin with 3 Balance Scale Uses

  • Context: Undergrad 
  • Thread starter Thread starter Samad
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Discussion Overview

The discussion revolves around a problem involving identifying a fake coin among ten coins using a balance scale, with the constraint of only three uses of the scale. Participants explore various strategies and express uncertainty about the solution.

Discussion Character

  • Exploratory, Debate/contested, Homework-related

Main Points Raised

  • One participant expresses uncertainty about the solution to the problem.
  • Another participant suggests using a graduated cylinder and water as an alternative method.
  • A participant proposes that it might be possible to solve the problem in two trials by dividing the coins into groups.
  • Another participant claims to have already solved a similar problem involving twelve coins and provides a link to that discussion.
  • A later reply challenges the feasibility of the two-trial solution, arguing that the first weighing does not provide useful information about the fake coin.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the solution, with multiple competing views and strategies presented, and some disagreement regarding the effectiveness of proposed methods.

Contextual Notes

Some assumptions about the properties of the coins and the nature of the fake coin (lighter or heavier) remain unaddressed. The discussion does not resolve the mathematical steps necessary to arrive at a solution.

Samad
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You have 10 coins and a balance scale. 1 coin is a fake, but you don't know whether it is lighter or heavier than the rest. You are only allowed to use the scale 3 times. Which coin is fake?

I don't know the answer to this problem.
 
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Can you use a graduated cylinder and water? ;-)
 
Try this:
90+ %
--- = balance scale;
1) 3 coinsA --- 3 coinsB than 2) 3 coinsA or B --- 3 coinsC than you know what group of 3 coins is lighter or heavier 3) spli the group ... 1 coin --- 1 coin and you solve it. But...if all 3 groups (A,B and C) are the same weight, the last coin is the one, but you don´t know if it´s lighter or heavier. :)

"Some times you don´t have to be exact, you have to be enough."
 
I´m sorry, that was 100%.
 
If one is lucky, it can be done in 2 trials. 5 v 5, 2 v 2, odd one out.
 
http://192.220.96.182/trap_a1.html#14

Separate the coins into 3 groups of 3 and a single (A, B, C, and S). Weigh A and B, then B and C (taking note of which is heavier or lighter in both weighings (if both weighings balance, then S is the counterfeit coin). Based on the two weighings you can tell which group of three had the counterfeit coin AND whether it was lighter or heavier than the others. You then weigh two of the three coins in the suspect group (one on each scale). If they balance, then the third coin of the group (not weighed) is the counterfeit. If they do not balance you will know which of the two is counterfeit because you were able to determine whether the counterfeit coin was heavier or lighter from the previous two weighings.
 
Last edited by a moderator:
GDBot said:
If one is lucky, it can be done in 2 trials. 5 v 5, 2 v 2, odd one out.

No, it can't. 5v5 will only tell you that one set is heavier than the other. Since you don't know what the fake coin is, the first weighting tells you nothing.
 

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