danago
Gold Member
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Hi. The question wants me to find the inverse of <br />
y = \frac{{x - 1}}{{x - 2}}<br />
Heres my working for it:
<br /> \begin{array}{l}<br /> x = \frac{{y - 1}}{{y - 2}} \\ <br /> xy - 2x = y - 1 \\ <br /> xy - y = 2x - 1 \\ <br /> (x - 1)y = 2x - 1 \\ <br /> y = \frac{{2x - 1}}{{x - 1}} \\ <br /> \end{array}<br />
The answer says something different though.
If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.
Thanks,
Dan.
Heres my working for it:
<br /> \begin{array}{l}<br /> x = \frac{{y - 1}}{{y - 2}} \\ <br /> xy - 2x = y - 1 \\ <br /> xy - y = 2x - 1 \\ <br /> (x - 1)y = 2x - 1 \\ <br /> y = \frac{{2x - 1}}{{x - 1}} \\ <br /> \end{array}<br />
The answer says something different though.
If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.
Thanks,
Dan.