Find the total number of ways of coloring the eight regions

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Homework Help Overview

The discussion revolves around a problem related to coloring eight regions, potentially involving concepts from graph theory and combinatorial counting methods.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest starting with simpler problems, consider the use of chromatic polynomials, and discuss the deletion-contraction theorem as a method for finding solutions. There is also speculation about the original poster's familiarity with graph theory.

Discussion Status

The conversation includes various approaches to the problem, with some participants expressing uncertainty about the complexity of the methods discussed. There is no explicit consensus on the best approach, but several lines of reasoning are being explored.

Contextual Notes

There are indications that the original poster may not be actively participating, and assumptions about their background in graph theory are being questioned. The discussion reflects a mix of perspectives on the problem's categorization and solution methods.

feesicksman
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Homework Statement
We have a figure which has been divided into 8 regions (A to H) as shown below. Each region must be colored in exactly one color. There are four colors to choose from: yellow, red, green and blue. There is only one other constraint: neighboring regions must not be of the same color.
Find the total number of ways of coloring the regions A to H.
Relevant Equations
I think this problem can be viewed as a vertex coloring procedure (with at most 4 colors) in graph theory.
image.jpg

The eight regions
 
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Please show your efforts to work on the problem. Thank you.
 
It may help to first work through a smaller, simpler problem.
 
If you know some graph theory, have you come across chromatic polynomials?
 
OP has not returned. The solution can be found by elementary counting, I don't think that categorising the problem as graph theory helps.
 
pbuk said:
The solution can be found by elementary counting,
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
 
haruspex said:
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...

haruspex said:
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
 
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pbuk said:
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
Very neat. Interestingly, it mirrors the deletion-contraction approach, in reverse order.
To be looking up vertex colouring, the OP first had to recognise the duality between vertices and regions.
 

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