Find the total number of ways of coloring the eight regions

Click For Summary
SUMMARY

The total number of ways to color eight regions can be calculated using the deletion-contraction theorem, yielding a result of 768. This approach is supported by elementary counting methods, although some participants suggested that graph theory concepts like chromatic polynomials may not be necessary for this specific problem. The discussion highlights the importance of recognizing the duality between vertices and regions in graph theory.

PREREQUISITES
  • Understanding of the deletion-contraction theorem
  • Basic knowledge of graph theory concepts
  • Familiarity with chromatic polynomials
  • Elementary counting techniques
NEXT STEPS
  • Study the deletion-contraction theorem in detail
  • Explore chromatic polynomials and their applications
  • Practice elementary counting problems for better understanding
  • Investigate the duality between vertices and regions in graph theory
USEFUL FOR

Mathematicians, computer scientists, and students studying graph theory or combinatorial problems, particularly those interested in coloring algorithms and their applications.

feesicksman
Messages
2
Reaction score
0
Homework Statement
We have a figure which has been divided into 8 regions (A to H) as shown below. Each region must be colored in exactly one color. There are four colors to choose from: yellow, red, green and blue. There is only one other constraint: neighboring regions must not be of the same color.
Find the total number of ways of coloring the regions A to H.
Relevant Equations
I think this problem can be viewed as a vertex coloring procedure (with at most 4 colors) in graph theory.
image.jpg

The eight regions
 
Physics news on Phys.org
Please show your efforts to work on the problem. Thank you.
 
It may help to first work through a smaller, simpler problem.
 
If you know some graph theory, have you come across chromatic polynomials?
 
OP has not returned. The solution can be found by elementary counting, I don't think that categorising the problem as graph theory helps.
 
pbuk said:
The solution can be found by elementary counting,
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
 
haruspex said:
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...

haruspex said:
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
 
  • Like
Likes   Reactions: scottdave
pbuk said:
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
Very neat. Interestingly, it mirrors the deletion-contraction approach, in reverse order.
To be looking up vertex colouring, the OP first had to recognise the duality between vertices and regions.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
4K
Replies
23
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K