MHB Find the unique solution to the IVP

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The discussion focuses on finding the unique solution to the initial value problem (IVP) defined by the differential equation $t^3y'' + e^ty' + t^4y = 0$ with conditions $y(1) = 0$ and $y'(1) = 0$. Participants suggest dividing through by $t^4$ to simplify the equation and consider the trivial solution $y(t) = 0$. It is confirmed that this trivial solution satisfies the initial conditions. There is also mention of the need to test the exactness of the solution method, although it is noted that this approach is typically for first-order equations. Ultimately, the trivial solution is recognized as a valid solution to the IVP.
shamieh
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Find the unique solution to the IVP

$t^3y'' + e^ty' + t^4y = 0$ $y(1) = 0$ , $y'(1) = 0$

Should I start out by dividing through by $t^4$

to get

$\frac{1}{t} y" + \frac{e^t}{t^4}y' + y = 0$
 
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I think in this case, you should look for a trivial solution to the given ODE. :D
 
what do you mean? should I plug y(1) = 0
 
Consider the function:

$$y(t)=0$$

Does it satisfy all of the given requirements?
 
Yes?
 
MarkFL said:
Consider the function:

$$y(t)=0$$

Does it satisfy all of the given requirements?

Oh wait.. I need to test this using the exact solution method don't i?

(testing whether it is exact or not)
 
shamieh said:
Oh wait.. I need to test this using the exact solution method don't i?

(testing whether it is exact or not)

That's for first order equations...to be honest, I would not know offhand how to find the general solution to the ODE associated with the IVP here, but I simply noticed that the trivial solution $y(t)=0$ satisfies the IVP. :D
 

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