A particle with a charge of 5.40nC is moving in a uniform magnetic field of B= -(1.20 )Tz^. The magnetic force on the particle is measured to be F=3.50×10−7N X^ + 7.60×10−7N Y^ .
Calculate the y component of the velocity of the particle.
F= qv x B
F = qvBSin(theta)
The Attempt at a Solution
lost trying to use the magnitude to find also
F/qb=Vsin(theta) doesnt seem to yield results yet :/