Finding a Min or Max point without knowing the function

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    Function Max Point
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Discussion Overview

The discussion revolves around the behavior of the composite function h(x) = f(g(x)), where f is a monotonically increasing differentiable function and g has a local minimum at x=0. Participants explore whether x=0 is a minimum, maximum, or neither for h(x) without knowing the explicit forms of the functions involved.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that since g(x) has a local minimum at x=0 and is locally increasing for x > 0 and locally decreasing for x < 0, h(x) must also exhibit similar behavior, suggesting a local minimum at x=0.
  • Another participant questions whether f has any effect on h, leading to a clarification that while f does not affect the locations of extrema, it influences the values of those extrema and the locations of zeroes.

Areas of Agreement / Disagreement

There is some agreement that x=0 is a local minimum for h(x), but the role of f in determining the nature of h(x) remains contested, indicating that the discussion is not fully resolved.

Contextual Notes

The discussion does not resolve the implications of differentiability for the functions involved, nor does it clarify how the specific properties of f might influence the behavior of h beyond the locations of extrema.

Yankel
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Hello,

I have this simple problem:

f(x) and g(x) are both differentiable. f is monotonically increasing for every x. g has a local min at x=0. we define h to be h(x)=f(g(x)).

Can we say anything about x=0 for h(x) ?

I used the chain rule to find that h'(x) = f'(g(x))*g'(x). at x=0 g'(x)=0, so h'(0) = 0 as well. is it possible to say if x=0 is min, max, or isn't is possible ?

thank you in advance.
 
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We can tell that g(x) is locally increasing for x > 0. Therefore h(x) is locally increasing for x > 0 as well.
And g(x) is locally decreasing for x < 0, so h(x) is locally decreasing for x < 0 as well.
Consequently h(x) has a local minimum at x=0.
Differentiability of any of the functions is not needed.
 
right, so f has no effect on h ?
 
Yankel said:
right, so f has no effect on h ?

Well, f doesn't affect the locations of the extrema, but it does affect the value of those extrema.
And f will also affect the locations of zeroes.
 

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