Finding angle between vectors u = (3,1,2) and v = (-2,3,4)

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pokerfan91
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ive got the formula down as angle=cos-1[(u.v)/(||U||||v||)

with my u as 3,1,2 and v as -2,3,4 this gives me cos-1[(-6i+3j+8k)/root406) where do i go from here?
 
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that is what the dot product is ment to give me isn't it i just have no idea where to go after that to get the angle
 
No it isn't. The dot product is supposed to give you a scalar (ie a number), but you wrote that it gives you a vector. You can't very well take the arccosine of a vector can you?
 
[tex]a\vec{i}+ b\vec{j}+ c\vec{k}\cdot d\vec{i}+ e\vec{j}+ f\vec{k}[/tex]
is defined as
[tex]ad+ be+ cf[/tex]
a number, NOT as
[tex]ad\vec{i}+ be\vec{j}+ cf\vec{k}[/tex]