Finding eigenvalues for a spin 1/2 spinor eigenvector

[Ed Quanta]

Ok, so let us suppose we have a spinor which is a spin 1/2 state vector

(a)
(b)

Now spinors exist in 2 dimensional complex space. How do I find the eigenvalues which correspond to the above eigenvector



I am confused because we are dealing with eigenvalues for a matrix which is not a square matrix. I know for a square matrix we just find the eigenvalues such that the determinant of the matrix becomes zero. I am not sure how to deal with determinants of non-square matrices however. Helo anybody?

 

[Galileo]

Eigenvectors only make sense for square matrices. Think about it. Suppose you have a mxn matrix and a nx1 vector. Multiplication will give a mx1 vector. In any case not a scalar multiple of itself.

The eigenvalues are determined by the matrix. not by the eigenvector itself. Si I can't answer the question:'How do I find the eigenvalues which correspond to the above eigenvector ' if I don't know the matrix.

EDIT: Whoops. This is physics ofcourse. The matrices you need are probably the Pauli spin-matrices. Use those.

 

[Dr Transport]

See the other post on this subject...