Finding flight time for a projectile launched at 62 degrees

[pebbles]

[SOLVED] Made a small mistake and can't figure out what to do-->Projectile motion

Homework Statement

Ball is launched at 62 degrees above horizontal at 22 m/s. What distance does the ball travel?

Homework Equations

x=x0+vx0t

The Attempt at a Solution

x0=0
vy0=22 m/s
y0=0
theta=62
vy0=22sin62=19 m/s
vx0=22cos62=10 m/s

but I messed up on my time calculation
t=vy0/gravity.
that's not right. what's the correct time calculation?

 

[rl.bhat]

t=vy0/gravity.
that's not right. what's the correct time calculation?
this time is to reach the maximum height. Total time is twice this time.

 

[pebbles]

ok, so i just need to multiply that value by 2? thank you.