Finding Force Exerted by Photons on a Sphere

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SUMMARY

The discussion focuses on calculating the force exerted by photons on a sphere of radius 1 cm subjected to light with an intensity of 0.5 W/cm². The initial scenario involves a perfectly absorbing sphere, where the force can be calculated using the formula derived from momentum transfer of absorbed photons. The second scenario discusses a non-perfectly absorbing sphere, suggesting that even with reflection, the force remains unchanged due to conservation of momentum principles. The calculations involve integrating the momentum of reflected photons over the sphere's surface.

PREREQUISITES
  • Understanding of photon momentum and energy transfer
  • Familiarity with calculus, particularly integration techniques
  • Knowledge of light intensity and its relation to force on surfaces
  • Concept of reflection and absorption in optics
NEXT STEPS
  • Study the principles of momentum transfer in photon interactions
  • Learn about the mathematical integration of functions in physics
  • Explore the differences between absorbing and reflecting surfaces in optics
  • Investigate the implications of conservation of momentum in various physical scenarios
USEFUL FOR

Physics students, optical engineers, and anyone interested in the mechanics of light-matter interactions.

cupid.callin
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I was given this question in my book …
A sphere of radius 1cm is placed in path of light of large aperture. The intensity of light is 0.5W/cm^2. The sphere completely absorbs photons falling on it. Find the force exerted by them on the sphere.
I solved the question and I have given the solution in the pic. Please have a look.

_________________________________________________________

Next there was another question given below it …
The same sphere is placed in same light but this time the sphere is not perfectly absorbing. Show that the force exerted by photons remains the same.

Well I have no idea how to prove the second one. Please someone help .
 
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that is easy, but you need a little more complicated calculus.
i think that this time it is a perfectly reflecting surface (a mirror) than it will reflect photons in all directions. there will be a spherical symetry, we can consider rings which will have same reflecting angles starting from r=0 to r=R (radius of sphere)
for an arbitrary r angle that is between line that is parallel to path of photons and normal is arcsin(r/R)
the area of that ring is 2(pi)rdr
if you draw what i explained, you will see that angle of reflected photon is 2.arcsin(r/R) call this angle 2(theta)
so momentum of one of reflected photons is -(h/lambda)cos(2theta) right? i couldn't follow your notation but let's assume there are n photons per unit area
Ptotalx=int(0toR) [-2(pi)n.r.h.cos(2arcsin(r/R))/lambda]dr
that will give sum of x components of momentums of reflected photons, you need deltaP to find force
it is Pinitial-Pfinal. Pfinal is result of the integral, P initial is what you found on you paper. I am sure you will understand the concept because at you notes you have wrote that Pfinal is 0 since photons are absorbed, here it is simple not zero. But these two do never give the same result.
 
Thanks a lot sigmaro!

I really helped ... question is solved!
 

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