Finding Formulas from Systematic Names: How Does the Number in Parentheses Help?

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Discussion Overview

The discussion revolves around understanding how the number in parentheses in systematic names of chemical compounds relates to their formulas, particularly focusing on compounds like sodium chlorate and potassium nitride. Participants explore the implications of oxidation states and the neutrality of molecules, with a mix of theoretical and practical considerations.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that the number in parentheses indicates the oxidation state of the element, specifically in sodium chlorate(V) where chlorine has an oxidation number of +5.
  • Another participant emphasizes the importance of the molecule being neutral and suggests assuming the charge on oxygen to be -2.
  • Concerns are raised about the nomenclature for potassium nitride(III), questioning whether it is a typo for potassium nitrate(III) or if it correctly refers to K3N.
  • Multiple participants attempt to calculate the number of oxygen atoms needed for neutrality in sodium chlorate(I) and sodium chlorate(V), with varying approaches and results.
  • One participant expresses uncertainty about deriving the formula solely from the name, indicating a need for clarity on the nomenclature system.
  • There is a reiteration that the nomenclature for oxysalts differs from traditional "ate" and "ite" systems, suggesting a broader context for understanding these compounds.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and agreement on how to derive formulas from systematic names, with some calculations leading to different interpretations. The discussion remains unresolved regarding the nomenclature of potassium nitride(III) and the exact implications of the oxidation states in determining molecular formulas.

Contextual Notes

Some participants' calculations depend on assumptions about oxidation states and the neutrality of molecules, which may not be universally accepted. The discussion also highlights potential confusion in nomenclature that could affect the interpretation of chemical formulas.

IDK10
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Homework Statement


Sodium chlorate(I)
Sodium chlorate(V)
Potassium nitride(III)
Phosphorus(III) chloride
Magnesium iodate(I)

Homework Equations


None

The Attempt at a Solution


I know the number in the bracket refers to what's before it, i.e. in sodium chlorate(V), the (V) means that the chlorine has an oxidation number of +5, but how does this help me find the fomula of the copound.

For example with sodium chlorate(V):
I know its made from sodium (Na+) ions, and chlorate(ClO3-) ions.
 
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Molecule must be neutral, assume charge on oxygen to be -2.
 
I'm not familiar with the use of this style for negative oxidation numbers, e.g. potassium nitride(III), if this is really K3N and not a typo for potassium nitrate(III) = potassium nitrite = KNO2.
 
Borek said:
Molecule must be neutral, assume charge on oxygen to be -2.
For sodium chlorate(I)
Na would be +1
Cl would be +1
and O would be -2
1 + 1 - 3(2) = -4 (what would I do with this?)

Or

Na + 1 -6 = 0
Na = 5 (?)

For sodium chlorate(V)
Na would be +1
Cl would be +5
and O would be -2
1 + 5 - 3(-2) = 0
NaClO3
 
.
 
How many oxygens are there in sodium chlorate(I)?
Note: in this nomenclature you must not get hung up on the notion that e.g. "chlorate" means "ClO3". All oxysalts are "ates" with different oxidation number of the central atom. This is quite different from the "ate", "ite", "per...ate" system.
 
mjc123 said:
How many oxygens are there in sodium chlorate(I)?
Note: in this nomenclature you must not get hung up on the notion that e.g. "chlorate" means "ClO3". All oxysalts are "ates" with different oxidation number of the central atom. This is quite different from the "ate", "ite", "per...ate" system.
I'm not sure, I have to find the formula just from the name. I know sodium chlorate(v) has 3.
 
IDK10 said:
For sodium chlorate(I)
Na would be +1
Cl would be +1
and O would be -2

And assuming one Na and one Cl, how many oxygens are needed for the molecule to be neutral?
 
Borek said:
And assuming one Na and one Cl, how many oxygens are needed for the molecule to be neutral?
While I was away, amd therefore didn't see your reply, I was thinking and I think i got it:
1 + 1 -2O = 0
-2O = -2
O = 1
NaClO?
 
  • #10
IDK10 said:
While I was away, amd therefore didn't see your reply, I was thinking and I think i got it:
1 + 1 -2O = 0
-2O = -2
O = 1
NaClO?

Yep.

Try with chlorate(III) and chlorate(V).
 
  • #11
Borek said:
Yep.

Try with chlorate(III) and chlorate(V).
Sodium chlorate(III):
1+3-2O=0
-2O=-4
O=2
NaClO2

Sodium chlorate(V):
1+5-2O=0
-2O=-6
O=3
NaClO3
 
  • #12
At least with these you should have no problems now :wink:
 

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