Finding how high a winch can lift a mass before the battery discharges

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Homework Help Overview

The discussion revolves around determining how high a winch can lift a mass before the battery discharges, focusing on the electrical and mechanical aspects of the system. The problem involves a D cell battery with specific voltage and capacity, a winch with variable load resistance, and a mass being lifted.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of power into work and the relationship between energy, power, and time. Questions arise about how to account for the winch's resistance and efficiency in calculations. There is also a consideration of how to maximize energy and the implications of resistance on energy loss.

Discussion Status

Some participants have provided clarifications regarding the total energy of the system and the role of efficiency. There is ongoing exploration of the relationship between current, resistance, and energy loss, with participants questioning assumptions and seeking to understand the implications of different factors on the problem.

Contextual Notes

Participants note the complexity of converting power to work without a clear time frame and the need to consider the efficiency of the winch in their calculations. There is mention of varying assumptions in subsequent problems, indicating a potential shift in the parameters being analyzed.

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Finding how high a "winch" can lift a mass before the battery discharges

Homework Statement



The EMF of the D cell battery is 1.5 V and the life is about 10 A/hr. 50% of the energy int he winch does actual work and the lifting mass is 50 kg. The winch has a load resistance variable of Rl.

Homework Equations


Total Power=VI-V^2/Rl

(1.5*10)-10^2/Rl Total power of the system since the question states that the winch's resistance is much greater than the battery's internal resistance. (Thus ignore battery's resistance.)


The Attempt at a Solution




After finding the total power of the system, I thought that convert the power into work and using mgh to find the max height of winch would work. But at this point, I do not understand how to convert power into work if I do not know the time. Am I to find the height in terms of hours? I've read the book and searched around the internet but the conversion between power and energy is confusing.


Thank You
 
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You are trying to fin the total ENERGY of the system.
power = V * I and energy = power * time = V * I * t

The capacity of the battery if 10 AHour (I*t) - you have written it down wrong.
 


O I see. That should help me quite a bit. Thank You
 


also, P is VI but don't I need to take into account the resistance of the winch it's self? Or does the 50% efficiency take into account of the resistance?
 


Yes the 50% efficency includes everything - the question is much simpler than you are imagining
 


so in the next problem, we have to assume that the 50% doesn't apply. I now have to find the Rl which would maximize the energy. ..

This is where I would apply the total energy-energy due to winch correct?

My question here is that how do I find energy loss due to the winch? Can i use E=I^2Rt? But I'm confused since I is squared. can I assume that 10 A*hour is just I also? so that energy is 10^2*Rl*t and power is 10^2Rl?
 

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