Finding Laplace transform of derivative of t² sin 7t

[escobar147]

Use the Laplace Transform of f (t) = t2 sin 7t to find the Laplace Transform
of f' (t) = 2t sin 7t + 7t2 cos 7t

also note that:

the laplace transform of t^2 sin ωt = (6ωs^2 - 2ω^3) / (s^2 + ω^2)^3


I don't even know how to approach this so any help whatsoever would be hugely appreciated

 

[HallsofIvy]

I would imagine that whoever gave you this problem expects you to know that the Laplace transform of f'(x) is f(0) plus s times the Laplace transform of f(x).