Finding Laplace Transform of F(s): A Struggling Student's Story

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SUMMARY

The Laplace transform of the function F(s) = (1/t)*(exp(2t)-1) is ln(s/(s-2)). The discussion highlights the confusion surrounding the Laplace transform of 1/t, which does not exist, and suggests using the power series expansion of (exp(2t)-1)/t to find a valid transform. Participants emphasize the importance of understanding the integration process and the conditions under which Laplace transforms can be applied. The conversation reveals a gap in foundational knowledge regarding Laplace transforms among students.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with exponential functions
  • Knowledge of power series expansions
  • Basic integration techniques
NEXT STEPS
  • Study the properties of Laplace transforms
  • Explore power series and their applications in transforms
  • Learn about the conditions for the existence of Laplace transforms
  • Practice integrating functions involving exponentials and polynomials
USEFUL FOR

Students studying differential equations, educators teaching Laplace transforms, and anyone seeking to improve their understanding of integral transforms in engineering and mathematics.

drew1435
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Homework Statement


find laplace transform of F(s)= (1/t)*(exp(2t)-1)


Homework Equations



stated answer: ln(s/(s-2))

The Attempt at a Solution


i really don't know where to start with laplace. my teacher has done a terrible job really jusut explaining the simplr process. Should i distrivute the 1/t first?? But the laplace of 1/t does not exist correct? so do i just integrate exp(-st)(exp(2t)/t)
 
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Right, the laplace transform of 1/t doesn't exist. But neither does the transform of exp(2t)/t. Look at the power series expansion of (exp(2t)-1)/t. The transform of that might exist.
 

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