Finding maximum and minimum of r=2-2cos(θ)

[Ashford]

Homework Statement

Find the Maximum and Minimum of the following equation.
r=2-2cos($$\Theta$$)

The Attempt at a Solution

Max- 2-2 cos (0$$\pi$$)=0
(0,0$$\pi$$);(0,2$$\pi$$)

Min 2-2cos($$\pi$$)=4
(4,$$\pi$$)

Do i just have these backwards?

 

[Dick]

0<4, so yes, you have them backwards. 4 is the max, 0 is the min.

 

[HallsofIvy]

I'm wondering how you determined that

Max- 2-2 cos (0)=0
(0,0[itex]\pi[/itex\);(0,2$\pi$)<br /> <br /> Min 2-2cos()=4<br /> (4,$\pi$)[/itex]

$<br /> And, by the way, an <i>equation</i> does <b>not</b> have a max or min- a <i>function</i> does. An equation does not even have a "value" to be max or min.$