Finding maximum velocity from kinetic and potential energy conservation

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Homework Statement



[PLAIN]http://img218.imageshack.us/img218/249/photoxl.jpg

Homework Equations



vmax = Sq(2gh)
Ei=Ef
mgh=mgh+.5mv^2
 
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For the first stone, how is it 'moving' at it's max height? Think about how the forces are acting and how the stone would be moving at the INSTANT it reaches its max height, this should give you a good hint as to how to treat the second stone.

For the case of the second stone you need to break it down into horizontal and vertical components. The motion of the second stone isn't entirely in the vertical direction, there is also a component in the horizontal direction. Break the initial velocity Vo into its vertical and horizontal components. What is 1 significant thing to remember about projectile motion? Apply that to find your solution.
 
Attached is my solution to the two questions. I strongly suggest you try to solve the problems on your own before going through my solution.
 

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