Velocity from Kinetic energy and work energy theorem

1. Oct 17, 2009

IAmSparticus

1. A 0.066 kg arrow is fired horizontally. The bowstring exerts an average force of 50 N on the arrow over a distance of 0.95 m. With what speed does the arrow leave the bow?

2. Work Energy Theorem = change in kinetic energy = (1/2*mass*Final Velocity^2)-(1/2*mass*Initial Velocity^2)

3. Since the initial speed is zero and the mass is given, I get a solution of 0, but that is most likely because I did the algebra wrong. I got an equation of Final Velocity = Square root (2*.066kg*0m/s)/(2*.066)

Which is clearly wrong. Where did I go wrong?

2. Oct 17, 2009

rl.bhat

What is the work done on the arrow?
Equate it to the kinetic energy of the arrow and find the velocity.