Calculating Velocity from Kinetic Energy: Solving for v in the r=mv/qb Formula

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    Joules Velocity
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Homework Help Overview

The discussion revolves around calculating the radius of a proton's circular path in a magnetic field using kinetic energy. The original poster is attempting to derive velocity from kinetic energy in the context of the formula r=mv/qb.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks to understand how to extract velocity from kinetic energy, questioning the relationship between Joules and velocity. Some participants provide the definition of kinetic energy and suggest using the formula 1/2 mv^2 to solve for v.

Discussion Status

The discussion is active, with participants exploring the definition of kinetic energy and its application to the problem. Guidance has been offered regarding the formula for kinetic energy, although no consensus on the next steps has been reached.

Contextual Notes

The original poster notes that the mass of the proton is not provided, which may affect the ability to solve for velocity directly.

baylorbelle
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A proton with a kinetic energy of 4.6×10−16 J moves perpendicular to a magnetic field of 0.26 T. What is the radius of its circular path?


I know the formula is r=mv/qb. the only thing not given is v. So my question is how do I get v from Joules? I know 1 Joule=1N/m, and that N=ma, but I don't know how to get velocity from that. Any help on that part would be greatly appreciated : )
 
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What's the definition of kinetic energy?
 
1/2 mv^2
 
baylorbelle said:
1/2 mv^2
There you go. Now you can solve for v using the given information. (You may have to look up the mass of a proton.)
 
thanks!
 

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