Finding mean of Y if Y=(X1+X2+X3)/3 given mean and variance of x's

  • Context: Undergrad 
  • Thread starter Thread starter ellyezr
  • Start date Start date
  • Tags Tags
    Mean Variance
Click For Summary
SUMMARY

The discussion centers on calculating the mean and variance of the sample mean Y, defined as Y = (X1 + X2 + X3)/3, where X1, X2, and X3 are random variables with mean μ and variance 1. It is established that the mean of Y is μ, regardless of whether the random variables are independent or not, due to the linearity of expectation. Additionally, if X1, X2, and X3 are independent, the variance of Y is confirmed to be 1/3.

PREREQUISITES
  • Understanding of random variables and their properties
  • Knowledge of linearity of expectation
  • Familiarity with variance calculations for independent variables
  • Basic statistics concepts, including mean and variance
NEXT STEPS
  • Study the concept of linearity of expectation in probability theory
  • Learn about variance of sums of random variables, particularly independent ones
  • Explore the implications of dependence and independence in statistical analysis
  • Review examples of calculating means and variances in different statistical contexts
USEFUL FOR

Students of statistics, data analysts, and anyone interested in understanding the properties of random variables and their distributions.

ellyezr
Messages
3
Reaction score
0
Let X1, X2, X3 be three random variables. Suppose all three have mean μ and variance 1. The sample mean is Y = (X1 +X2 +X3)/3.
(a) Can you compute the mean of Y? If so, what is it? If not, why not?

I have that it is either μ OR that it is not possible to find, since we don't know if they are independent or not (as it says later in the question). I have a strong feeling that it is the latter, but I am not sure.

(b) If we assume that the three random variables are independent, what would the variance of Y be?
1/3 right? Just to be sure.
 
Physics news on Phys.org
You should have notes on how to combine distributions.
How did you calculate the values you have suggested?
 
y=(x1+x2+x3)/3
x1 = x2 = x3 = mu
y=(mu+mu+mu)/3
y=3mu/3=mu

or can you not do that because you don't know if they are independent or not?

and no, I don't notes on that - trust me, I looked before I posted.
 
OK - well the first part seems to be saying you know nothing about the distributions on the ground that they are random. However, since the means are the same, does it make a difference?

The second part says they are independent - but nothing else - does that matter?

Or is the context of the problem important for figuring out what it all means?

Since you have no notes on this, you should try looking some up.
It would help me help you if I knew what level this should be answered at and if this forms part of a formal course.
 
ellyezr said:
Let X1, X2, X3 be three random variables. Suppose all three have mean μ and variance 1. The sample mean is Y = (X1 +X2 +X3)/3.
(a) Can you compute the mean of Y? If so, what is it? If not, why not?

I have that it is either μ OR that it is not possible to find, since we don't know if they are independent or not (as it says later in the question). I have a strong feeling that it is the latter, but I am not sure.

(b) If we assume that the three random variables are independent, what would the variance of Y be?
1/3 right? Just to be sure.

a) Averaging is linear - dpendence is irrelevant. E(Y) = μ
b) Yes.
 
thank you mathman
 

Similar threads

Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
6K