Finding pH of solutions with an acid and base

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SUMMARY

The discussion focuses on calculating the pH of a solution formed by mixing 0.040 mol of KOH with 2.00 L of 0.020 M HCl. The reaction involves KOH and HCl, both strong acids and bases, resulting in water and KCl. The key to determining the final pH lies in identifying the limiting reagent and recognizing that if both reactants are completely consumed, the solution will consist solely of water and KCl, leading to a neutral pH. Additionally, participants suggest considering ionic strength in the calculations.

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  • Understanding of acid-base reactions, specifically strong acids and bases.
  • Knowledge of pH calculations and the concept of limiting reagents.
  • Familiarity with chemical equilibrium and Ka values.
  • Basic principles of ionic strength and its effects on solution properties.
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  • Learn about the concept of limiting reagents in chemical reactions.
  • Research the effects of ionic strength on pH and chemical equilibria.
  • Explore the properties of strong acids and bases, focusing on their dissociation in solution.
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Chemistry students, educators, and professionals involved in analytical chemistry or chemical engineering who require a deeper understanding of acid-base reactions and pH calculations.

mirandab17
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What is the pH of the solution formed when 0.040 mol KOH is added to 2.00 L of 0.020 m HCl?

Hello all!

I'm really struggling with this. I set up the change table with the reaction of KOH + HCl <> H2O + KCl, and so I end up with Ka = x/(.01-x)(0.2-x). What Ka value would I use?

I may be completely wrong. Please help.
 
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Both are strong, so it is just a limiting reagent question. Whatever is left is responsible for the final pH. If nothing is left, than you have just water solution of NaCl.

Could be you are expected to take ionic strength into account.
 

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