What is the pH of the solution formed when 0.040 mol KOH is added to 2.00 L of 0.020 m HCl? Hello all! I'm really struggling with this. I set up the change table with the reaction of KOH + HCl <> H2O + KCl, and so I end up with Ka = x/(.01-x)(0.2-x). What Ka value would I use? I may be completely wrong. Please help.