Finding Refraction Angle and Wavelength in Water for Sodium Light?

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SUMMARY

The discussion focuses on calculating the refraction angle and wavelength of sodium light (λ=5893 Å) in water, given an incident angle of θ=35°. Using Snell's Law (n_a sin(θ_a) = n_b sin(θ_b)) and the index of refraction for water (n=1.33), the wavelength in water is determined to be λ=4431 Å. The correct application of the formula λ=λ_0/n confirms this calculation, ensuring accurate results for the refraction of light in different media.

PREREQUISITES
  • Understanding of Snell's Law
  • Familiarity with the concept of wavelength in different media
  • Knowledge of the index of refraction
  • Basic principles of light behavior at interfaces
NEXT STEPS
  • Research the derivation and applications of Snell's Law
  • Explore the concept of wavelength changes in various materials
  • Learn about the optical properties of different liquids
  • Investigate the effects of temperature on the index of refraction
USEFUL FOR

Students in physics, optical engineers, and anyone studying the behavior of light in different mediums will benefit from this discussion.

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A narrow beam of sodium light (λ=5893 A) is incident from air on a smooth surface water at θ=35°. Find the refraction angle and wavelength in water.

n=λ_0/λ:wavelength of light in a material
n_asinΘ_a=n_bsinΘ_b: snells law
n=c/v:index of refraction

I tried using the wavelength of light in a material to find n. I got confused because λ will equal each other. I am not sure if it is correct. Please help. Thanks
 
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You need to look up what n is for water, then apply the equation to find the wavelength in water.
 
n=λ_0/λ
λ=λ_0/n, water n=1.33, and λ_0=5893
λ=5893/1.33= 4431 A Is this correct?
 

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