Finding Refraction Angle and Wavelength in Water for Sodium Light?

In summary, to find the refraction angle and wavelength of a narrow beam of sodium light (λ=5893 A) incident on a smooth water surface at θ=35°, we can use the equation n=λ_0/λ to find the index of refraction in water. By looking up the value of n for water (1.33) and substituting it with the given values, we can calculate the wavelength in water to be 4431 A.
  • #1
h20proof
5
0
A narrow beam of sodium light (λ=5893 A) is incident from air on a smooth surface water at θ=35°. Find the refraction angle and wavelength in water.

n=λ_0/λ:wavelength of light in a material
n_asinΘ_a=n_bsinΘ_b: snells law
n=c/v:index of refraction

I tried using the wavelength of light in a material to find n. I got confused because λ will equal each other. I am not sure if it is correct. Please help. Thanks
 
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  • #2
You need to look up what n is for water, then apply the equation to find the wavelength in water.
 
  • #3
n=λ_0/λ
λ=λ_0/n, water n=1.33, and λ_0=5893
λ=5893/1.33= 4431 A Is this correct?
 

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