MHB Finding Solutions for $y'=Ay$ with Vector and Matrix Components

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SUMMARY

The discussion centers on solving the differential equation $y' = Ay$ where the coefficient matrix is $A = \begin{bmatrix} 4 & 1\\ 4 & 4 \end{bmatrix}$. The eigenvalues of this matrix are determined to be $\lambda_1 = 6$ and $\lambda_2 = 2$, indicating that the system has a proper node that is unstable. To find the general solution, one must derive the solutions for both components of the vector $y$ and combine them accordingly.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors in linear algebra
  • Familiarity with differential equations, specifically linear systems
  • Knowledge of matrix operations and properties
  • Ability to manipulate and solve vector equations
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  • Learn how to derive general solutions for systems of linear differential equations
  • Explore stability analysis of dynamical systems
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ineedhelpnow
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I think this should be my last question :D It's a question i missed on my last exam and have no idea how to do it and I wanted to quickly go over because my final is in a few hours so if anyone could help that would be awesome

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Hi! (Wave)

The coefficient matrix for this system is $A=\begin{bmatrix}
4 & 1\\
4 & 4
\end{bmatrix}$, for which we determine the eigenvalues $\lambda_1=6$ and $\lambda_2=2$, which are both positive real values.
What can we deduce from that?
 
I'm thinking proper node that's unstable (Tmi)
 
ineedhelpnow said:
I'm thinking proper node that's unstable (Tmi)

(Nod)
 
How do i find the general solution of it though?
 
ineedhelpnow said:
How do i find the general solution of it though?

Which is the form of the solution of $y'=Ay$ ?
 
Right. Is the solution for both supposed to be found and then put together?
 
ineedhelpnow said:
Right. Is the solution for both supposed to be found and then put together?

In this case, if we have $y'=Ay$, $y$ is a vector and $A$ is a matrix.
You can find from this the general solution.
Thus you will find to what the vector $y$ will be equal and so you will have also the solution of $y_1$ and $y_2$.
 

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