Finding speed of a string given length, mass, and velocity of wave

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SUMMARY

The discussion focuses on calculating the speed of a wave on two strings with different masses but the same length and tension. The correct formula to use is v = sqrt(T/μ), where T is the tension and μ is the linear mass density. For the first string, the linear mass density is calculated as 3.0 g/50.0 cm, resulting in 0.06 g/cm. The second string, having half the mass, has a linear mass density of 0.03 g/cm, but both strings travel at the same speed of 5.0 m/s due to equal tension.

PREREQUISITES
  • Understanding of wave mechanics
  • Familiarity with the concept of linear mass density (μ)
  • Knowledge of the tension in strings
  • Ability to manipulate and solve equations involving square roots
NEXT STEPS
  • Study the derivation of the wave speed formula v = sqrt(T/μ)
  • Explore the effects of tension on wave speed in different materials
  • Learn about the relationship between mass density and wave propagation
  • Investigate how wave speed varies with different string lengths and tensions
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Students in physics, particularly those studying wave mechanics, as well as educators and tutors looking to clarify concepts related to wave speed and string properties.

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Homework Statement


A string is 50.0 cm long and has a mass of 3.0 g. A wave travels at 5.0 m/s along the string. A second string has the same length, but half of the mass of the first. If the two strings are under the same tension, what is the speed of the second string?


The Attempt at a Solution


I don't know which equation to start with. I tried to find omega (w) using w=sqrt(g/l) and then using v=wrt. I don't think this is right. Can someone point me in the right direction?
 
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The correct equation is v=sqrt(T/μ), where T is the tension and μ is the linear mass density (mass divided by length). In this problem, the linear mass density of the two strings is different, so the velocity of the second string will be different. The linear mass density of the first string is 3.0 g/50.0 cm = 0.06 g/cm. The linear mass density of the second string is half of that, so it is 0.03 g/cm. Plugging these values into the equation, we get v = sqrt(T/0.03 g/cm) = sqrt(T/0.03) m/s. Since we know the tension is the same in both strings, the speed of the second string will also be the same, 5.0 m/s.
 

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