1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the coefficient of friction (mew) DUE TOMOROW

  1. Feb 18, 2008 #1
    Finding the coefficient of friction (mew) DUE TOMOROW :(

    Our physics class went curling, and this is the data we had to collect..

    Without Sweeping

    Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Trial 6 Trial 7
    Time (s) 21.37 21.70 21.65 21.95 20.47 20.69 22.30
    Distance (m) 115.50 145.50 125.50 112.00 28.00 28.50 261.50

    With Sweeping

    Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Trial 6 Trial 7
    Time (s) 22.06 20.75 24.31 21.50 22.13 21.87 18.15
    Distance (m) 147.00 75.50 320.00 18.00 255.00 198.00 42.00

    Distances are measured past the second hog line, add 868 inches, and convert to metres.

    Mass of Stone = 20 kg (2 sig. digs)
    1 ft. = 0.3048 m

    One of the question asks to: Calculate the average coefficients of friction with and without sweeping.

    So I calculated the Fn = (20)(9.81) = 196.2 N

    But the Force of Friction = (mew) * (Fn)

    How am i supposed to find the force of friction? So then i can find the (mew)

    someone pleaseeeee help
     
  2. jcsd
  3. Feb 18, 2008 #2
    i suppose you could assume the decceleration due to friction was linear in time so, knowing the final speed, time and distance, you could calculate the decceleration and hence the force using the "vusat" equations
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?