Finding the Concentration of Triiodide

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SUMMARY

The discussion centers on determining the concentration of triiodide (I3-) in a solution after adding potassium iodide (KI). The user initially assumed that the I3- concentration would be diluted by the volume of KI added. However, the professor clarified that KI does not simply dilute I3-; instead, it can participate in the formation of I3- under certain conditions. The correct approach involves understanding the equilibrium between I3- and I- in the presence of I2, which was not initially considered by the user.

PREREQUISITES
  • Understanding of chemical equilibria and reaction dynamics
  • Familiarity with the formation of triiodide from iodide and iodine
  • Knowledge of molarity and concentration calculations
  • Basic laboratory techniques for mixing and measuring solutions
NEXT STEPS
  • Study the equilibrium reactions involving I3-, I-, and I2 in aqueous solutions
  • Learn about the principles of dilution and concentration calculations in chemistry
  • Research the role of potassium iodide in triiodide formation
  • Explore laboratory techniques for accurate concentration measurement, such as spectrophotometry
USEFUL FOR

Chemistry students, laboratory technicians, and educators seeking to understand the dynamics of triiodide formation and concentration calculations in solution chemistry.

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Homework Statement


Stupid question but I'm not sure about it.

In lab we added I3- and KI into a test tube and from this we have find the concentration of I3- in the final volume.


The Attempt at a Solution


Would the I3- be diluted by the KI that was added or does the KI end up forming i3- once in solution? I know that I- will form I3- if I2 is present but what about if just I3- is present. Originally I just calculated the concentration assuming the I3- would be diluted by the volume of KI but my professor said that was not correct...

Any help would be really appreciated.
 
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