Finding the Eigen Value of A.σ Vector Product

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SUMMARY

The eigenvalue of the scalar product of an arbitrary vector A with the Pauli matrices, represented as A.σ, is definitively ±|A|. This scalar product results in a 3x3 matrix formed by the sum of the components of A multiplied by the corresponding Pauli matrices. The eigenvalues correspond to eigenspinors aligned with the direction of vector A, confirming that the eigenvalues are indeed ±|A|.

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rupesh57272
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Can anyone tell me what is eigen value of product of a vector with pauli matrices i.e
A.σ where A is an arbitrary vector ?
 
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welcome to pf!

hi rupesh57272! welcome to pf! :smile:

i don't follow you :redface:

A.σ is a vector, so how does it have eigenvalues? :confused:
 
He means a sort of 'scalar' product, which would be (after performing the sum) a 3x3 matrix which can have eigenvalues.

\vec{A}\cdot\vec{\sigma} = A_{x}\sigma_x + A_{y}\sigma_y + A_{z}\sigma_z.
 
ohh!

then won't they be eigenspinors rather than eigenvectors, in the directions of ±A, and with eigenvalue |A| ?
 


Sorry I forgot to mention that it is scalar product of a Vector and Pauli Spin matrices. What is the Eigen Value of it ?
 
I think it should be ±|A|
 
sorry, yes, ±|A| :smile:

eg for Sz, or for S-z, the two eigenspinors are the same …

spinor in the z direction (which we call spin-up, with positive eigenvector, for Sz and spin-down, with negative eigenvector, for S-z)

spinor in the minus-z direction (which we call spin-down, with negative eigenvector, for Sz and spin-up, with positive eigenvector, for S-z) :wink:
 

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