Finding the General Solution for xX' = aX

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SUMMARY

The general solution for the differential equation \( xX' = aX \) is derived as \( X = Ax^a \). The discussion highlights the process of rearranging the equation into a separable form, leading to the integration of both sides. The initial confusion regarding the notation is clarified by emphasizing that \( X \) is indeed a function of \( x \). The correct approach involves separating variables and integrating, confirming the solution's validity.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with the concept of separable differential equations
  • Knowledge of integration techniques
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the method of solving separable differential equations
  • Learn about integrating factors in first-order ODEs
  • Explore the application of differential equations in real-world scenarios
  • Investigate advanced topics in ODEs, such as stability analysis
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Students and professionals in mathematics, particularly those studying differential equations, as well as educators seeking to enhance their teaching methods in this area.

naspek
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Question: find the general solution of xX' = aX

i know it's kinda simple ode.. but, i just don't know y i can't get the correct answer..

solution..

xX' = aX
x dX/dx = aX
d/dx X = aX/x
X = ∫aX/x dx
X = aX ln |x| + C

the general solution is Ax^a

problem : i can't get the correct answer..
 
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is X a function x? if so that's prettty messy notation

how about starting with
[tex]xy'(x) = ay[/tex]

then
[tex]x\frac{dy}{dx} = ay[/tex]

the idea when rearranging is to "separate" the DE, so group all the y's on one side & x's on the other side - if you can do that it means its a "seperable DE"
[tex]\frac{dy}{x} = a\frac{dx}{x}[/tex]

now try intergating both sides
 

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