Finding the General Solution for xX' = aX

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naspek
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Question: find the general solution of xX' = aX

i know it's kinda simple ode.. but, i just don't know y i can't get the correct answer..

solution..

xX' = aX
x dX/dx = aX
d/dx X = aX/x
X = ∫aX/x dx
X = aX ln |x| + C

the general solution is Ax^a

problem : i can't get the correct answer..
 
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is X a function x? if so that's prettty messy notation

how about starting with
[tex]xy'(x) = ay[/tex]

then
[tex]x\frac{dy}{dx} = ay[/tex]

the idea when rearranging is to "separate" the DE, so group all the y's on one side & x's on the other side - if you can do that it means its a "seperable DE"
[tex]\frac{dy}{x} = a\frac{dx}{x}[/tex]

now try intergating both sides