Finding the Inductor in an RL Circuit

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SUMMARY

The discussion focuses on calculating the inductance values in RL and RLC circuits using the half-life formula. For the RL circuit with a resistance of 22Ω and a half-life of 64.00µs, the inductance is determined to be 79.69µH. In the RLC circuit, with a resistance of 1000Ω and a capacitance of 11.63µF, the inductance is calculated as 8.22mH. The relevant equation used is t 1/2 = 0.693(L/R), which is rearranged to find L.

PREREQUISITES
  • Understanding of RL and RLC circuit theory
  • Familiarity with the half-life formula in electrical circuits
  • Basic knowledge of inductance and resistance units
  • Ability to perform calculations involving exponential decay
NEXT STEPS
  • Study the derivation and applications of the half-life formula in electrical engineering
  • Learn about the behavior of RLC circuits at resonance
  • Explore the impact of varying resistance and capacitance on inductance calculations
  • Investigate practical applications of inductors in circuit design
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing RL and RLC circuits for academic or practical applications.

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Homework Statement



I'm trying to find the inductor

RL Circuit:
Resistor (22Ω), Inductor , Function Generator
Resistance (Ω): 24.7 Ω 50

RL Circuit Half-Life: 64.00µs

RLC Circuit, Resonance:
Resistor (1000Ω), Inductor , Function Generator
Resistance (Ω): 1080 Ω 50

Capacitance: 11.63µf
Sine Wave Frequency at Resonance (voltage plots): 1.960 Hz
Sine Wave Frequency at Resonance (Lissajous figures): 550 Hz


Homework Equations


I'm not sure since there are so many on my lab sheet, but is it: t 1/2= 0.693(L/R)


The Attempt at a Solution



rearrange to (R* t 1/2)/0.693= L ?
 
Physics news on Phys.org
For the RL circuit, (22* 64.00µs)/0.693= 79.69µHFor the RLC Circuit, (1000* 11.63µf)/0.693= 8.22mH
 

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