Finding the Range & Domain of y = 24 - 2x

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Discussion Overview

The discussion revolves around determining the range and domain of the function y = 24 - 2x. Participants explore the conditions under which both y and x remain positive, examining the implications of these conditions on the values of x and y.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant asks for the range and domain of the function, stating that both y and x must be positive.
  • Another participant calculates that x can only be up to 12 to keep y positive, leading to the conclusion that 0 < x < 12.
  • A third participant confirms the earlier calculations, stating that y must also be less than 24, resulting in the range 0 < y < 24.
  • However, a later post suggests an alternative answer of 6 < x < 12 and 0 < y < 12, questioning the accuracy of the previous conclusions.
  • Another participant agrees with the alternative answer, asserting that the previous conclusions are incorrect.

Areas of Agreement / Disagreement

There is disagreement regarding the correct domain and range of the function, with some participants supporting the initial conclusion of 0 < x < 12 and 0 < y < 24, while others propose 6 < x < 12 and 0 < y < 12 as the correct answer.

Contextual Notes

The discussion includes various interpretations of the conditions for x and y, and the implications of these conditions on the domain and range. There is uncertainty regarding the correctness of the answers provided, particularly in relation to the reference material.

okunyg
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I'm sorry for this, but what is the range and domain of the following function?

y = 24 - 2x

y has to be positive (y > 0) and x too (x > 0)

How would you solve this? Do you just need a look and then be able to write it down? Or do you need to solve it with algebra?

I've found that x can only be up to 12, or else y would be negative:

y = 24 - 2x
0 = 24 - 2x
x = 12

What is then the minimum of x?

2x = 24 - y
0 = 24 - y
y = 24

When y is 24, x is zero.

This means:
0 < x < 12

With these values, y is always positive, we have solved the domain of the function.

Is this correct?
 
Last edited:
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okunyg said:
This means:
0 < x < 12

With these values, y is always positive, we have solved the domain of the function.

Is this correct?
That's right.
 
y > 0 implies 24 - 2x > 0 implies x < 12

x > 0 implies 12 - 0.5y > 0 implies y < 24

So: 0 < x < 12

And: 0 < y < 24

Good work. Also, don't apologise for wanting help.
 
Thanks.


But apparently the correct answer is:

6 < x < 12 and
0 < y < 12

Is the key (answer) in the back of the book misprinted perhaps?
 
okunyg said:
Thanks.


But apparently the correct answer is:

6 < x < 12 and
0 < y < 12

Is the key (answer) in the back of the book misprinted perhaps?

yes completely wrong
 

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